418. Sentence Screen Fitting

Given a rows x cols screen and a sentence represented by a list of non-empty words, find how many times the given sentence can be fitted on the screen.

Note:

  1. A word cannot be split into two lines.
  2. The order of words in the sentence must remain unchanged.
  3. Two consecutive words in a line must be separated by a single space.
  4. Total words in the sentence won't exceed 100.
  5. Length of each word is greater than 0 and won't exceed 10.
  6. 1 ≤ rows, cols ≤ 20,000.

Example 1:

Input:

rows = 2, cols = 8, sentence = ["hello", "world"]


Output:

1


Explanation:

hello---
world---

The character '-' signifies an empty space on the screen.

Example 2:

Input:

rows = 3, cols = 6, sentence = ["a", "bcd", "e"]


Output:

2


Explanation:

a-bcd- 
e-a---
bcd-e-

The character '-' signifies an empty space on the screen.

Example 3:

Input:

rows = 4, cols = 5, sentence = ["I", "had", "apple", "pie"]


Output:

1


Explanation:

I-had
apple
pie-I
had--

The character '-' signifies an empty space on the screen.

Solution

(1) Java

class Solution {
    public int wordsTyping(String[] sentence, int rows, int cols) {
        if (sentence == null || sentence.length == 0) {
            return 0;
        }
        String sen = String.join(" ", sentence)+" ";
        int len = sen.length();
        int start = 0;
        for (int i = 0; i< rows; i++) {
            start += cols;         
            while (start >= 0 && sen.charAt(start%len) != ' ') {
                start--;
            }
            start++;
        }
        return start/len;
    }
}

(2) Python

class Solution:
    def wordsTyping(self, sentence, rows, cols):
        """
        :type sentence: List[str]
        :type rows: int
        :type cols: int
        :rtype: int
        """
        if not sentence:
            return 0
        start = 0;
        sent = " ".join(sentence)+ " "
        length = len(sent)
        for i in range(rows):
            start += cols
            while start >= 0 and sent[start%length] != " ":
                start -= 1
            start += 1
        return int(start/length)

(3) Scala



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