734. Sentence Similarity

Given two sentences words1, words2 (each represented as an array of strings), and a list of similar word pairs pairs, determine if two sentences are similar.

For example, "great acting skills" and "fine drama talent" are similar, if the similar word pairs are pairs = [["great", "fine"], ["acting","drama"], ["skills","talent"]].

Note that the similarity relation is not transitive. For example, if "great" and "fine" are similar, and "fine" and "good" are similar, "great" and "good" are not necessarily similar.

However, similarity is symmetric. For example, "great" and "fine" being similar is the same as "fine" and "great" being similar.

Also, a word is always similar with itself. For example, the sentences words1 = ["great"], words2 = ["great"], pairs = [] are similar, even though there are no specified similar word pairs.

Finally, sentences can only be similar if they have the same number of words. So a sentence like words1 = ["great"] can never be similar to words2 = ["doubleplus","good"].

Note:

The length of

words1

and

words2

will not exceed

1000

.

The length of

pairs

will not exceed

2000

.

The length of each

pairs[i]

will be

2

.

The length of each

words[i]

and

pairs[i][j]

will be in the range

[1, 20]

.

Solution

(1) Java



(2) Python

class Solution:
    def areSentencesSimilar(self, words1, words2, pairs):
        """
        :type words1: List[str]
        :type words2: List[str]
        :type pairs: List[List[str]]
        :rtype: bool
        """
        if not words1 and not words2:
            return True
        elif not words1 or not words2:
            return False
        elif len(words1) != len(words2):
            return False
        for i in range(len(words1)):
            word1 = words1[i]
            word2 = words2[i]
            if word1 == word2:
                continue
            found = False
            for pair in pairs:
                if word1 in pair and word2 in pair:
                    found = True
                    break
            if not found:
                return False
        return True

Concise code

class Solution(object):
    def areSentencesSimilar(self, words1, words2, pairs):
        if len(words1) != len(words2): return False

        pairset = set(map(tuple, pairs))
        return all(w1 == w2 or (w1, w2) in pairset or (w2, w1) in pairset
                   for w1, w2 in zip(words1, words2))

(3) Scala



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